6-6x=3x^2-10x+4

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Solution for 6-6x=3x^2-10x+4 equation:



6-6x=3x^2-10x+4
We move all terms to the left:
6-6x-(3x^2-10x+4)=0
We get rid of parentheses
-3x^2-6x+10x-4+6=0
We add all the numbers together, and all the variables
-3x^2+4x+2=0
a = -3; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·(-3)·2
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{10}}{2*-3}=\frac{-4-2\sqrt{10}}{-6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{10}}{2*-3}=\frac{-4+2\sqrt{10}}{-6} $

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